MnO2 + 4HCl = Cl2 + MnCl2 + 2H20How many grams of MnCl2 will be produced when 4.75 moles

MnO2 + 4HCl = Cl2 + MnCl2 + 2H20How many grams of MnCl2 will be produced when 4.75 moles of MnO2 react with excess HCl